The full-load copper loss of a transformer is 1600 W. At half-load, the copper loss will be

A.6400 W
B.1600 W
C.800 W
D.400 W

Answer: D

Explanation:
Copper loss in a transformer is given by the formula:

Copper Loss = I^2R

where I is the current flowing through the transformer and R is the resistance of the copper windings.

Since copper loss is proportional to the square of the current, it can be assumed that at half-load, the current flowing through the transformer will be half of the full-load current. Therefore, the copper loss at half-load can be calculated as follows:

Copper Loss at Half-Load = (1/2)^2 x Full-Load Copper Loss

Copper Loss at Half-Load = (1/4) x 1600 W

Copper Loss at Half-Load = 400 W

Therefore, the correct answer is option D, i.e., 400 W.

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